Find the value of k for which one root of the quadratic equation kx^2-14x+8=0 is six times the other.
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αβ=c/a
6β²=8/k
β²=4/3k---------1
α+β=14/k
7β=14/k
196k²/9=196
k²=9
k=3
your answer
6β²=8/k
β²=4/3k---------1
α+β=14/k
7β=14/k
196k²/9=196
k²=9
k=3
your answer
Nazirose:
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