find the value of k, for which one root of the quadratic equation kx²-14x+8=0 is 2.
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Hlloooo..
k(2)²-14(2)+8=0
4k-28+8=0
4k-20=0
4k=20
k=5
k(2)²-14(2)+8=0
4k-28+8=0
4k-20=0
4k=20
k=5
Rajiv01:
hi
hlo
Answered by
0
x=2
So the value of k is----
kx²-14x+8=0
k*(2)^2 - 14*2 + 8 =0
4k - 28 + 8 =0
4k = 28-8
4k = 20
k = 20/4
k = 5
_________________
THE VALUE OF k is 5.
I hope its help u so mark me as the BRAINLIST FRIEND___:-)
So the value of k is----
kx²-14x+8=0
k*(2)^2 - 14*2 + 8 =0
4k - 28 + 8 =0
4k = 28-8
4k = 20
k = 20/4
k = 5
_________________
THE VALUE OF k is 5.
I hope its help u so mark me as the BRAINLIST FRIEND___:-)
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