Question

find the value of k, for which one root of the quadratic equation kx²-14x+8=0 is 2.

Answer 1

Hlloooo..
k(2)²-14(2)+8=0
4k-28+8=0
4k-20=0
4k=20
k=5

Answer 2

x=2

So the value of k is----

kx²-14x+8=0

k*(2)^2 - 14*2 + 8 =0

4k - 28 + 8 =0

4k = 28-8

4k = 20

k = 20/4

k = 5

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THE VALUE OF k is 5.

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