Question

find the value of k, for which one root of the quadratic equation kx²-14x+8=0 is 2.

Answer 1

hai mate ots ur amswer

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

If one root of equation is 2
so x = 2
put it in the equation, We get
$k(2) {}^{2} - 14 \times 2 + 8 = 0 \\ 4k - 28 + 8 = 0 \\ 4k - 20 = 0\\ 4k = 20 \\ k = \frac{20}{4} \\ k = 5$
Hope it helps you