Question

Find the value of k for which the given equation has equal roots

(k-12) x2+2(k-12)x+2=0

Answer 1

Roots r real and equal that means they r 0
Also, b²-4ac=0
Here,2k-24+2k-24+2=0
Wait.. Is it x or Multiplication sign

Answer 2

Hey mate thank for the question
Hope it helps
For equal roots
D=0
d=b2-4ac
d=(2(k-12)2-4*(k-12)*2
d=4(k2+144-24k)-8k+96
d=4k2+576-96k-8k+96
d=4k2+672-104k
d=4(k2-26k+168)
d=k2-26k+168
d=k2-(14+12)k+168
d=k2-14k-12k+168
d=k(k-14)-12(k-14)
d=(k-14)(k-12)
k=12,k=14