Question

Find the value of k for which the given value is a solution of the given equation: x2+3ax+k=0,x=-a

Answer 1

Given equation: x^2+3ax+k=0
putting the value x= -a
(-a)^2+3a(-a)+k=0
a^2-3a^2+k=0
-2a^2+ k=0
k=2a^2

Answer 2

Answer:

$k = 2 {a}^{2}$

Step-by-step explanation:

for explanation, see the photo.