Question

find the value of k for which the pair of linear equation 6x+ky=36 and 2x-3y=12
had infinitely many solutions​

Answer 1

Answer:

a^6 + a^3 - 8a^3 - 8

= a^3 ( a^3 + 1) - 8 ( a^3 + 1)

= (a^3 - 8)(a^3 + 1)

= [ (a)^3 - (2)^3] [ (a)^3 +(1)^3]

= (a-2)(a^2 + 2a + 4)(a+1)(a^2 - a + 1)

hope this helps

Step-by-step explanation: