find the value of k for which the pair of linear equation 6x+ky=36 and 2x-3y=12
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Answer:
a^6 + a^3 - 8a^3 - 8
= a^3 ( a^3 + 1) - 8 ( a^3 + 1)
= (a^3 - 8)(a^3 + 1)
= [ (a)^3 - (2)^3] [ (a)^3 +(1)^3]
= (a-2)(a^2 + 2a + 4)(a+1)(a^2 - a + 1)
hope this helps
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