Find the value of k for which the point (-1,3) liye on the graph of the linear equation 2x-y+k=0
Answers
Answered by
2
Answer:
k=5
Step-by-step explanation:
x= -1
y=3
2(-1)-3+k=0
-2-3+k=0
-5+k=0
k=0+5
k=5
Similar questions