Question

find the value of k for which the quadraic equation 2 X square + kx + 3 equals to zero has real equal roots

Answer 1

Answer:

2root6

Step-by-step explanation:

For equal roots

K^2 - 4x2×3 = 0

K^2 = 24

K = 2root6

Answer 2

Answer:

Step-by-step explanation:

2x²+kx+3=0

B²-4ac>0

K²-4(2)(3)>0

K²<24

K<±2√6

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