Question

find the value of k for which the quadratic equation kx(x-2) +6 = 0 has real and equal roots.

Answer 1

Given Equation
kx(x-2) +6 = 0

kx^2 -2kx +6 = 0

a = k , b = -2k c = 6

Also its given that ..This quadratic equation has Real and equal roots..

so b^2 - 4ac = 0

(-2k)^2 - 4(k)(6) = 0

4k^2 - 24k = 0

4k(k-4) = 0

4k=0 ; k-4 = 0

k= 0/4 = 0 ; k= 4

so the roots are 0,4

k = 6..