Question

Find the value of k for which the system of equntions
kx-y=2 and 6x-2y = 3 has a unique solution.
OR​

Answer 1

Answer:

$equation \: 1 \\ k x - y = 2 \\ here \: a1 = k \\ b1 = - 1 \\ c1 = 2 \\ \\ equation \: 2 \\ 6x - 2y = 3 \\ here \: a2 = 6 \\ b2 = - 2 \\ c2= 3 \\ \\ for \: unique \: solution \: \frac{a1}{a2}≠  \frac{b1}{b2} \\ \\ therefore \: \frac{k}{6} ≠  \frac{ - 1}{ - 2} \\ \\ k≠  \frac{1}{2} \times 6 \\ \\ k≠ 3 \\ \\ therefore \: k \: can \: be \: any \: number \: other \: than \: 3$

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