Find the value of K, if (2x+3) is factor of 2xcube-9xsquare-x+k.
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2
x= -3/2
2(-3/2)^3-9(-3/2)^2+3/2+k=0
k= 25.5
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2(-3/2)^3-9(-3/2)^2+3/2+k=0
k= 25.5
plz zzz mark it brainlist
JOEL71:
What is the value of k?
25.5
Answered by
3
2x+3=0
x=_3/2
2×(-3/2)^3 -9(-3/2)^2 -(-3/2) + k=0
-27/8 -81/4 + 3/2 +k=0
-27-162 +12 +8k /8 =0
-177 +8k =0
k=177/8
x=_3/2
2×(-3/2)^3 -9(-3/2)^2 -(-3/2) + k=0
-27/8 -81/4 + 3/2 +k=0
-27-162 +12 +8k /8 =0
-177 +8k =0
k=177/8
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