find the value of k if 4x^2+ KX +k-3 =0 has Equal roots
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Since the roots are equal
Discriminent = 0
=> b^2 - 4ac = 0
=> k^2 - 4(4)(k-3) = 0
=> k^2 - 16k +48 = 0
=> k^2 - 12k - 4k +48 = 0
=> k(k-12) - 4(k-12) = 0
=> (k-4)(k-12) = 0
=> k = 4 and 12
Discriminent = 0
=> b^2 - 4ac = 0
=> k^2 - 4(4)(k-3) = 0
=> k^2 - 16k +48 = 0
=> k^2 - 12k - 4k +48 = 0
=> k(k-12) - 4(k-12) = 0
=> (k-4)(k-12) = 0
=> k = 4 and 12
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