Question

Find the value of k if roots are equal of 2x^2+kx+3=0

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\large k=2\sqrt{6}$

Step-by-step explanation:

$\large \text{Given p(x)=2x^2+kx+3 }\\\\\\ \large \text{Roots of p(x) are equal}\\\\\\ \large \text{we have to find value of k}\\\\\\ \large \text{From discriminant we know formula for equal roots.}\\\\\\ \large \text{D= b^2-4ac=0 }\\\\\\ \large \text{where b is coefficient of x term }\\\\\\ \large \text{ a is coefficient of x^2 term }\\\\\\ \large \text{c is coefficient of constant term }$

$\large \text{putting values here}\\\\\\ \large p(x)=2x^2+kx+3\\\\\\ \large k^2-4\times2\times3=0\\\\\\ \large k^2-24=0\\\\\\ \large k^2=24\\\\\\ \large k=\sqrt{24} \\\\\\ \large k=\sqrt{2\times2\times2\times3} \\\\\\ \large k=2\sqrt{6} \\\\\\\large \text{Thus we get value of k=2\sqrt{6} }$