Question

Find the value of 'k' if the distance between (k,-2)and (3,-4) is √7.

Answer 1

Answer:

0.464,6.464

Step-by-step explanation:

The value of k are -0.464,6.464

Step-by-step explanation:

A=(x_1,y_1)=(k,2)

B=(x_2,y_2)=(3,4)

Distance =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}(x2−x1)2+(y2−y1)2

We are given that  the distance between the points ( k,2) and (3,4) be 8

So, 8 =\sqrt{(3-k)^2+(4-2)^2}8=(3−k)2+(4−2)2

8^2 =(3-k)^2+(4-2)^282=(3−k)2+(4−2)2

16 = 3^2 +k^2-6k+416=32+k2−6k+4

16=13+k^2-6k16=13+k2−6k

k^2-6k-3=0k2−6k−3=0

k=-0.464,6.464

Hence The value of k are -0.464,6.464

#Learn more:

Find the value of k if slope of joining point (3,4) and (k,2) is -3