Question

find the value of k if the equation has real roots ​

Answer 1

Answer:

k=4

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Answer 2

$\huge {\red{\boxed{ \overline{ \underline{ \mid\mathfrak{An}{\mathrm{sw}{ \sf{er}} \colon\mid}}}}}}$

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➠ Given :

3x² - k√3x + 4 = 0 is a equation which has real and equal roots.

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➠ To Find :

We have to find the value of K for which equation has real and equal roots.

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➠ Solution :

We know the case of the real and equal roots.

$\Large{\star{\boxed{\sf{b^2 - 4ac = 0}}}}$

Where

• a = 3
• b = -k√3
• c = 4

(Putting Values)

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$\sf{(-k \sqrt{3})^2 - 4(3)(4) = 0} \\ \\ \sf{\mapsto 3k^2 - 48 = 0} \\ \\ \sf{\mapsto 3k^2 = 48} \\ \\ \sf{\mapsto k^2 = \frac{\cancel{48}}{\cancel{3}}} \\ \\ \sf{\mapsto k^2 = 16} \\ \\ \sf{\mapsto k = \sqrt{16}} \\ \\ \sf{\mapsto k = \pm 4}$