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Given, AD = BC and angle DAB = angel CBA.
prove that : (I) triangle ABD = triangle BAC
(II) BD = AC
(III) angle ABD = angle BAC
proof : (I) In triangle ABD and BAC ,
AD = BC ( Given ) ................(side)
angle DAB = angle CBA ( Given ).........(angle)
AB = CD ( Parallel to each other ) ......(side)
By SAS criteria :
triangle ABD congruent to triangle BAC.
(II) Therefore, BD = AC ( CPCT).
(III) ALSO , angle ABD = angle BAC ( CPCT ).
MARK AS BRAINLIST PLZZZ...............
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