Question

Find the value of k if the points A(2, 3), B(4, k) and C(6, –3) are collinear.

Answer 1

as the 3 points are collinear then the area of triangle is 0
0=1/2[2(k+3)+4(3-3)+6(3-k)]
2k+6+0+18-6k=0
24-4k=0
4k=24
k=6

Answer 2

$\huge \pink \star{ \green{ \boxed{ \boxed{ \boxed{ \purple{ \mathfrak{Answer :}}}}}}} \pink\star$

k=0

REFER TO THE ATTACHMENT

Hope it Helps

FOLLOW