Question

Find the value of 'k' if the zero of the polynomial p(x)=xsquare+k(x)-10 is 3 ?

Answer 1

if the value of 'x' = 3
= x^2+kx-10 
⇒ (3)^2+k(3)-10 = 0
⇒ 9+3k-10 = 0
⇒ -1+3k = 0
⇒ 3k= 1
⇒ k= 1/3
 therefore the value of k = 1/3
 i hope that this will help u................^_^

Answer 2

  Given, 3 is the zero of the polynomial
  so, p(3) = 0
 xsquare + k(x) - 10 =0
  3square + 3k-10 = 0
       9     + 3k -10 = 0
    -1 + 3k = 0
       3k = 1
      k = 1/3