Find the value of k if x=2 is the solution of kx^2+2x-9=0
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Answered by
1
kx² + 2x - 9 = 0
when x = 2,
k(2)² + 2(2) - 9 = 0
4k + 4 - 9 = 0
4k - 5 = 0
4k = 5
k = 5/4
Answer: k = 5/4
Answered by
0
Here is your answer :-
P(x) = kx² +2x -9 =0
P(2) = k (2)² + 4 -9 =0
= 4k -5 =0
= k = 5/4
P(x) = kx² +2x -9 =0
P(2) = k (2)² + 4 -9 =0
= 4k -5 =0
= k = 5/4
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