Find the value of 'k' if (x-3) is a factor of 3x' + kx + 6 = 6
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Answer:
k=-9
Step-by-step explanation:
p(x)=3x^2+kx+6=6
g(x)=x-3
p(3)=3×3^2+k×3+6=6
=3×9+3k+6=6
=27+3k+6=6
=33+3k=6
=3k=6-33
=k=-27/3
=k=-9
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