find the value of k in equation
x² - kx +6=0 has real and unequal roots
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whats wrong ?
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x^2-kx+6=0
x^2-kx= -6
-kx=-6+x^2
-k=-6+x^2/x
-k=-6+x
k=6-x
Therefore, value of k =(6-x)
x^2-kx= -6
-kx=-6+x^2
-k=-6+x^2/x
-k=-6+x
k=6-x
Therefore, value of k =(6-x)
whats wrong ??
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