CBSE BOARD X, asked by sahil7247, 1 year ago

Find the value of k in quadratic equation KX(x-2)+6=0,so that they have two equal roots.

Answers

Answered by rrrr29
85

b ^{2}  - 4ac = 0
for equal roots it shuld be equal to zero
ie.
Attachments:
Answered by Cricetus
2

Given:

⇒  kx(x-2)+6=0

To find:

Value of k = ?

Solution:

From the given equation, we get

⇒  kx^2-2kx+6=0

here,

a = k

b = -2k

c = 6

If they have two equal roots, then

⇒  b^2-4ac=0

On substituting the values, we get

⇒  (-2k)^2-4\times k\times 6=0

⇒                4k^2-24k=0

On adding "24k" both sides, we get

⇒      4k^2-24k+24k=24k

⇒                          4k^2=24k

⇒                             k=\frac{24}{4}

⇒                             k=6

Thus the value of k is "6".

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