Question

Find the value of k in the terms of p and q such that the quadratic equation
(p-q) square X2+2(p saquare-q saquare)X+k=0 has equal roots and pis not equal to q.​

Answer 1

Step-by-step explanation:

x²-2(p²-q²)x+k=0

Let the roots be a, a

a+a=2(p²-q²)

2a=2(p²-q²)

a=(p²-q²)

a²=k

(p²-q²)²=k