Question

Find the value of k in this question

Answer 1

Hey Vansh,

Any equation is identity when it is equal to zero.

k(k^2 -1 )x^2+(k^2-4k+3)x+(k^2-3k+2) is an identity when it is =0

I.e k(k^2 -1)=0
,(k^2-4k+3)=0
,(k^2-3k+2)=0

=>k(k^2-1)=0=>k=0 or k=1 or k=-1..(i)

=>(k^2-4k+3=0)=>(k^2-3k-k+3)=0

=>k(k-3)-1(k-3)=0=>k=3 or k=1..(ii)

=>(k^2- 3k+2)=0=>k^2-k-2k+2=0

=>k(k-1)-2(k-1)=0=>k=2 or k=1..(iii)

From eq i,ii and iii

k=1 is the common solution for all.

Hence, k=1.

Hope it helps