Question

Find the value of k of x+1 is a factor of p(x)=kx^2-root2x+2

Answer 1

Answer:

Step-by-step explanation:

(x+1) is a factor of the given polynomial.

Therefore,

x + 1 = 0

x = -1

P(x) = 0

p(x) = kx² - √2x + 2 = 0

Putting the value of x in ,

kx² - √2x + 2

k* (-1)² - √2 * (-1) + 2

k * 1 + √2 + 2

k + √2 + 2 = 0

k + √2 = -2

k = -2 - √2.

Therefore ,

The value of k is k = -2 - √2.

Answer 2

Answer:

Step-by-step explanation:

Hey mate!

x+1=0

x=-1

p(x)=kx^2-√2x+2=0

k(-1)^2-√2(-1)+2=0

-k+√2+2=0

-k=-√2-2

k=√2+2

Hope it will help you!!!