Find the value of k so that the following equations have infinite solutions :
3x-y-5 = 0 ; 6x-2y+k=0
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Answered by
8
for infinite solutions
a1/a2=b1/b2=c1/c2
3/6=-1/-2=-5/k
1/2=1/2=-5/k
-5/k=1/2
k=-10
hope it helps
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a1/a2=b1/b2=c1/c2
3/6=-1/-2=-5/k
1/2=1/2=-5/k
-5/k=1/2
k=-10
hope it helps
please mark it as brainliest
Answered by
1
k= -10
a1/a2 =3/6 =1/2 b1/b2=-1/-2=1/2 c1/c2 = -5/k
and a1/a2 =b1/b2 =c1/c2 give infinite solution
so -5/-10 =1/2 which satisfies the equation
a1/a2 =3/6 =1/2 b1/b2=-1/-2=1/2 c1/c2 = -5/k
and a1/a2 =b1/b2 =c1/c2 give infinite solution
so -5/-10 =1/2 which satisfies the equation
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