Question

find the value of k so that the quadratic equation has equal roots:(k -5)x*2 + 2(k-5)x + 2 = 0

Answer 1

Step-by-step explanation:

It is given that the expression ax

2

+bx+6=0 doesn't have distinct real roots.

⇒ The graph of the function doesn't cross the x-axis.

⇒ The expression f(x)=ax

2

+bx+6 is always greater than or equal to zero.

Hence, f(x)≥0.

⇒ f(2)=a(2)

2

+b(2)+6≥0

⇒ 4a+2b+6≥0

⇒ 2a+b+3≥0

⇒ 2a+b≥−3

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