find the value of k so that the zeroes of qudratic polynomial 3ײ-k×+14 are in ratios 7:6
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let the zeros of quadratic polynomial are a &b
given, a/b = 7/6
a= 7b/6.........(1)
sum of zeros a+b = -( coefficient of x)/(coefficient of x²)
a+b = k/3..........(2)
hence products of zeros a×b= constant /( coefficient of x²)
a×b=14/3
for equn.1
(7b/6)×b= 14/3
b²= (14/3)×(6/7)
b²=4
b= +2&-2
hence a=7/3& -7/3
from equn. (2)
value of k are... 13 & -1
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