Math, asked by seleena3, 1 year ago

find the value of K, where KX (x+3)=9 having real equal roots

Answers

Answered by dhanushri

0

(x+3)=9
x=9-3
x=6 there x is equal to 6 in this equation

Answered by kaurgarv1207

2

Kx sq.+3kx =9
Kx sq.+ 3kx -9=0
9k sq.+ 36 k =0
9k(k+4)=0
K=0,-4

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