Question

find the value of k which the given systems of equation have infinite solutions kx-5y=2 2x-3y=12 ​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Eq-1:kx-5y-2=0. → A1=k, b1=-5, C1=-2

2x-3y-12 =0. →a2=2, b2=-3, c1-12.

The condition when equations have infinitely many solutions is:

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

By considering first two equal fraction:

$\frac{a1}{a2} = \frac{b1}{b2} = > \frac{k}{2} = \frac{5}{3} = > k = \frac{5 \times 2}{3}$

$k = \frac{10}{3}$