Math, asked by rupinderkaur1716, 10 months ago

Find the value of :- (log sin 1° + log sin 2° ………..+ log sin 89°) + (log tan 1° + log tan 2° + ……… + log tan 89°) - (log cos 1° + log cos 2° + ……… + log cos 89°)
\\frac{log√2}{(1+√2)}\\)
-1
1
None of these

Answers

Answered by narasimhabhagavan
1

answer is log(√2/1+√2)

Attachments:
Answered by sarivuselvi
0

Step-by-step explanation:

tan(45)=1

Log tan45

=log(1)

=0*0

=0

Similar questions