Question

find the value of log3 log2 log√3^81 ?
a) 2
b) 0
c) 1
d) -1

Answer 1

Solution...

$log_{3} \: log_{2} \: log_{ \sqrt{3} } \: 81 \\ = log_{3} \: log_{2} \: log_{ \sqrt{3} } (\sqrt{3}) ^{8} \\ = log_{3} \: log_{2} \: 8 log_{ \sqrt{3} } \sqrt{3} \\ = log_{3} \: log_{2}(2) ^{3}\\ = log_{3}(3) \: log_{2}(2) \\ = log_{3}(3)\\ = 1$
Hence,
C) 1, is the correct answer.

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Answer 2

$\huge\fbox\red{A}\fbox\pink{n}\fbox\purple{S} \fbox\green{w}\fbox\blue{E}\fbox\orange{r}$

1 is the answer.