Question

find the value of m and n so that y⁴+my³+2y²-3y+n is divisible by y²-1​

Answer 1

Step-by-step explanation:

when y²-1 is divisible

then

y²-1=0

y=1

f(y)=y⁴+my³+2y²-3y+n

f(1)=0

1⁴+ m1³+2×1²-3×1+n=0

1+m+2-3+n=0

m+n=0

m=(-n)

n=n

or

n=(-m)

m=m