Question

Find the value of m so that (2/9)^3 × (2/9)^-6 =(2/9)^2m-1.

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

given,

${ (\frac{2}{9}) }^{3} \times { (\frac{2}{9} )}^{ - 6} = {( \frac{2}{9}) }^{2m - 1} \: \: \: \: \: \: \: \: \: \:$

=>

${ (\frac{2}{9}) }^{3 - 6} = {( \frac{2}{9})}^{2m - 1}$

=>

${( \frac{2}{9}) }^{ - 3} = { (\frac{2}{9}) }^{2m - 1}$

on comparing the exponents

2m -1 = -3

=> 2m = -3 +1

=> 2m = -2

=> m = -2/2

=> m = -1 .

the value of m is -1

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