Question

Find the value of m so that m+2, 4m-6 and 3m-2 are the three consecutive terms of an A.P.

Answer 1

Hi ,

First term = a1 = m + 2 ,

a2 = 4m - 6 ,

a3 = 3m - 2

a2 - a1 = a3 - a2

4m - 6 - ( m + 2 ) = 3m - 2 - (4m - 6 )

4m - 6 - m - 2 = 3m - 2 - 4m + 6

3m - 8 = - m + 4

3m + m = 4 + 8

4m = 12

m = 12/4

m = 3

I hope this helps you.

: )

Answer 2

Hi,


Please see the attached file!


Thanks