Question

Find the value of x+y,if 3x-2y=5 and 3y-2x=3

Answer 1

Answer:

8

Step-by-step explanation:

Given : $3x-2y=5$

            $3y-2x=3$

To Find: x+y

Solution :

$3x-2y=5$ -----a

$3y-2x=3$  ---b

Solve a and b by substitution method .

Substitute the value of x from equation a in b

$3y-2(\frac{5+2y}{3})=3$

$\frac{9y-10-4y}{3}=3$

$9y-10-4y=9$

$5y-10=9$

$5y=19$

$y=\frac{19}{5}$

Substitute the value of y in a to get value of x

$3x-2\frac{19}{5}=5$

$\frac{15x-38}{5}=5$

$15x-38=25$

$15x=25+38$

$15x=63$

$x=\frac{63}{15}$

$x=\frac{21}{5}$

So, $x+y= \frac{21}{5}+\frac{19}{5}$

$x+y= \frac{40}{5}$

$x+y=8$

Hence the value of x+y is 8

                       

Answer 2

Step-by-step explanation:

Find the value of x+y, if 3x-2y=5 and 3y-2x=3