Question

Find the value of n in the mopecular formula of BenAl2Si6O18

Answer 1

Hi,



This is the example of cyclic silicate with the general formula (SiO3)n2n-

Since there are 6 silicon atoms thus -2n = -12, to balance the charge beryllium and aluminium are present. Aluminium has +3 charge and there are two aluminium atoms thus +6 charge is balanced .now + 6 charge is left which has to be balanced by beryllium. Be has +2 charge thus, there should be three beryllium atoms to balance the whole molecule. Thus n=3.

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Answer 2

Concept introduction:

Using chemical element indicators, numbers, and occasionally additional symbols, a chemical formula conveys information about the chemical proportions of the atoms that make up a specific chemical product or unit.

Given:

Here the given molecular formula is $BenAl2Si6O18$.

To find:

Here we have to find the value of $n$ of the compound.

Solution:

According to the question, This is the example of cyclic silicate with the general formula $(SiO3)n2n$- Since there are $6$ silicon atoms thus $-2n = -12$, to balance the charge beryllium and aluminum are present. Aluminum has $+3$ charge and there are two aluminum atoms thus $+6$charge is balanced .now$+ 6$ charge is left which has to be balanced by beryllium. Be has $+2$ charge thus, there should be three beryllium atoms to balance the whole molecule. Thus $n=3$.

Final answer:

Here we have done the calculation and the value of $n$ is $+3$ and this is our final answer also.

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