Question

find the value of n rise to m+n if m^2=32 where m and n are positive integer

Answer 1

➡HERE IS YOUR ANSWER⬇

Now,

${m}^{2} = 32 \\ \\ or \: \: {m}^{2} = ( {4 \sqrt{2} })^{2} \\ \\ so \: \: m = 4 \sqrt{2} \: \: since \: m > 0$

Now,

${n}^{m + n} \\ \\ = {n}^{(4 \sqrt{2} + n) } \\ \\ = {n}^{4 \sqrt{2} } . {n}^{n}$

⬆HOPE THIS HELPS YOU⬅