Math, asked by rachitjaiswal21, 9 months ago

find the value of
n²+6n-72/n-6​

Answers

Answered by pal69
12

Answer:

(n²+6n-72) /(n-6)

(n²+12n-6n-72) /(n-6)

(n+12) (n-6) /(n-6)

=n+12

Answered by divyamyindia271
3

Answer:

 {n}^{2}  + 6n - 72 \div n - 6 \\  \sqrt[n - 6]{n^{2} + 6n - 72 }  \\   \sqrt[n - 6]{ {n}^{2} + 6n - 72 }   |n \\  \:  \:   - (n  \:  \:  \:  + 6n) \\  =  =  =  =  =  =  =  =  =  =  =  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   - 72 \\  \\  \\  \\  \\  \\  \\  \\

so quotient is n and remainder is -72.

HOPE IT HELPS......

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