Math, asked by viren1230, 1 year ago

Find the value of p(2/3) for p(y)=2y^3-y^2-13y-6

Answers

Answered by sumanththescientist

p(2/3)=2(2/3)^3-(2/3)^2-13(2/3) -6
=2(8/27)-(4/9)-26/3-6
=16/27-4/9-26/3-6
=(16-12-234-162)/27
=-392/27

please mark as brainiest please please please

viren1230: thanks for helping but you wen I saw your first step i got the question but till then it to late

sumanththescientist: I taught of something that I ve done wrong

sumanththescientist: please mark as brainiest please please please please

viren1230: what bro

viren1230: ok i will

Answered by jogesh8

p(y)=2(2/3)^3-(2/3)^2-13(2/3)-6
= 2×(8/27)-(4/9)-(26/3)-6
= (16/27)-(4/9)-(26/3)-6
=16-12-234-162÷27
=-392/27
hope it's gonna help you buddy

viren1230: yes bro it helps me

jogesh8: your welcome

viren1230: :-)

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