find the value of p, for which one of the quadratic equation
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one root of Px² -14x +8 =0 is 6 times of another root ∅ , so,
sum of roots = ∅ +6∅ = 14/P
7 ∅ = 14/P
∅= 2/P -----(1)
products of roots = 6∅² = 8/P
put equation (1)
6(2/P )² = 8/P
24/P² = 8/P
3/P² =1/P
P = 3
sum of roots = ∅ +6∅ = 14/P
7 ∅ = 14/P
∅= 2/P -----(1)
products of roots = 6∅² = 8/P
put equation (1)
6(2/P )² = 8/P
24/P² = 8/P
3/P² =1/P
P = 3
abhi178:
now ,see the answer !!!
ok
tap red heart if this correct or satisfied you
great answer sir
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