Question

find the value of p for which one root of quadratic equation px^2-14x+8=0 is 6 times the other .

Answer 1

given that a = 6b
a+ b = 14/ p
ab = 4/p
6b+b = 14/p
6b×b = 8/p
7b = 14/p, b=2/p... eq 1
6b^2 =8/p, 3(2/p)^2 =4/p....(from eq 1)
p = 3