Question

find the value of p for which the equation to 2pX2+ 6X+ 5=0 has real and equal roots​

Answer 1

Answer:

By using equation

$a {x}^{2} + bx + c$

we can say

$a = 2p \: \: \: \: b = 6 \: \: \: \: c = 5$

Since roots are real and equal

Therefore

$d = 0$

$d = b^{2} - 4ac$

$0 = {6}^{2} - 4 \times 2p \times 5 \\ \\ 0 = 36 - 40p \\ - 40p = - 36 \\ p = \frac{36}{40} \\ p = \frac{9}{10}$