Question

Find the value of p for which the equation TX square minus 5x plus t equal to zero has equal roots

Answer 1

TX2-6X+T=0 HAS TWO EQUAL ROOTS.
SO,
$\sqrt{ {b }^{2} - 4ac } = 0$
$\sqrt{ {5}^{2} - 4 \times t \times t } = 0 \\ \sqrt{25 - 4 {t}^{2} } = 0 \\ 25 - 4 {t}^{2} = 0 \\ - 4 {t}^{2} = - 25 \\ 4 {t }^{2} = 25 \\ {t}^{2} = 25 \div 4 \\ t = \sqrt{25 \div 4 } \\ t = 5 \div 2$
4t2=25
t2=25/4
t=5/2.
THE VALUE OF T IS 5/2.