find the value of p,for which the points (-1,3),(2,p) and (5,1) are collinear
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Hy !
for collinear !
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
-1(p+1)+2(-1-3)+5(3-p)=0
-p-1-8+15-5p=0
-6p+6=0
6p=6
p=1 ans
for collinear !
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
-1(p+1)+2(-1-3)+5(3-p)=0
-p-1-8+15-5p=0
-6p+6=0
6p=6
p=1 ans
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