Question

Find the value of p for which these points are collinear (7,-2) (5,1) (3,p).

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

p = 4

Step-by-step explanation:

Since points are collinear,

so, x₁ ( y₂ - y₃ ) + x₂ ( y₃ - y₁ ) + x₃ ( y₁ - y₂ ) = 0

Now we take ( 7, -2 ) as ( x₁ , y₁ ) ( 5, 1 ) as ( x₂ , y₂ ) and ( 3 , p ) as ( x₃ , y₃ )

⇒ 7 ( 1 - p ) + 5 ( p + 2 ) + 3 ( -2 - 1 ) = 0

⇒ 7 - 7p + 5p + 10 - 6 - 3 = 0

⇒ -7p + 5p + 10 + 7 - 9 = 0

⇒ -2p + 17 - 9 = 0

⇒ -2p + 8 = 0

⇒ -2p = -8

⇒ p = $\frac{-8}{-2}$

⇒ p = $\frac{8}{2}$                                                     ∵ minus symbol gets cancelled

                                          p = 4

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By Abhiram5566

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