find the value of p if the equation x^2+ px+36=0 has equal roots
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Answer:
p = ±12
Step-by-step explanation:
For equal roots, D = 0
As we know, D = b² - 4ac
Quadratic equation: x² + px + 36 = 0
From the given quadratic equation,
a = 1
b = p
c = 36
So, b² - 4ac = 0
(p)² - 4 (1) (36) = 0
p² = 144
p = ±12
or, p = -12, +12
Thanks!
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