Question

find the value of p in real root where equation is 2xsquare +px+18=0​

Answer 1

Answer:

harami sala

thankyou for your understanding

Answer 2

Answer:

12

Step-by-step explanation:

For the roots to be real, using the quadratic formula, the Discriminant must be non-negative.

So

D≥0

b2−4ac ≥ 0

b²-4*2*18 ≥ 0

b²-144 ≥ 0

p² ≥ 144 ( b is p )

p ≥ 12

here p is must be positive .