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Given:-
∠ABC = ∠ACM
To prove:-
∠ABL = ∠ACM
Proof:-
In △ABC,
∠ABC = ∠ACB .......(1)..{given}
•°• side AB=AC ......{ side opposite to congruent angles are congruent}
•°• △ABC is an Isosceles triangle
now,
∠ABL = ∠BAC + ∠ACB ...(2)...{remote exterior angle}
And,
∠ACM =∠BAC + ∠ABC ....(3)..{remote exterior angle}
from (1), (2) and (3)
∠ABL = ∠ACM
Hence proved that,
∠ABL = ∠ACM,,
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