find the value of point (-1,3)lies on the graph of the equation 2x-y+k=0
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Put x = -1
And y = 3
2(-1)-3+k = 0
-2-3 +k = 0
K=5.
And y = 3
2(-1)-3+k = 0
-2-3 +k = 0
K=5.
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